0=(-6)^2-4*3*c

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Solution for 0=(-6)^2-4*3*c equation: 



0=(-6)^2-4*3c

We move all terms to the left:

0-((-6)^2-4*3c)=0

We add all the numbers together, and all the variables

-((-6)^2-4*3c)=0



We calculate terms in parentheses: -((-6)^2-4*3c), so:

(-6)^2-4*3c

determiningTheFunctionDomain
-4*3c+(-6)^2

We add all the numbers together, and all the variables

-4*3c+36

Wy multiply elements

-12c+36

Back to the equation:

-(-12c+36)



We get rid of parentheses

12c-36=0

We move all terms containing c to the left, all other terms to the right

12c=36

c=36/12

c=3

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